Every driver on the rode needs to have auto insurance, but the best provider for an individual can depend on where they live. Not all providers will offer the same price for the same protection in every city. Auto insurance prices can differ by hundreds of dollars each year in cities only a few hours apart. A new study by ValuePenguin determined the cheapest and most expensive cities to purchase auto insurance in certain states including Louisiana, Ohio, Illinois and Florida.
In Louisiana, the five cheapest cities for auto insurance had an average costs of $1,429 per year, which is 14 percent lower than the state average of $1,656. The cheapest cities were: Minden, Ruston, Bossier City, Shreveport and Bastrop. The most expensive cities were New Orleans, Arabi, Kenner, Denham Springs and Hammond. Overall, ValuePenguin determined the small cities in Louisiana tended to have lower auto insurance costs.
In Ohio, ValuePenguin found the five cheapest cities were Brunswick, Findlay, Bowling Green, Mentor and Cuyahoga Falls. The five most expensive cities for auto insurance in Ohio were Youngstown, Euclid, Lakewood, Cleveland and Toledo. Brunswick had the best yearly rate at $557, which was 25.7 percent lower than the state average.
ValuePenguin found in Illinois the most expensive cities for auto insurance were Cicero, Skokie, Berwyn, Oak Park and Chicago. Some of the cheapest cities were Galesburg, Quincy, Bloomington, Normal, Champaign and Kewanee. Cicero's yearly average auto insurance rate was $1,061 and Chicago's average yearly rate was $957. Quincy was the cheapest city at $667, 19.7 percent below the state average.
The most expensive place for auto insurance in Florida is Miami at $2,198 each year, according to ValuePenguin, and the cheapest is Bristol with an average $836 per year. The state average is $1,098 per year, making Miami's rate more than double the state average.